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Javascript list members of groups

patrickvanhoof

Hi,

I have following code to list members of Alfresco groups:

var siteGroups = new Object(); 
var logFile = space.childByNamePath("GroupAndUsers.txt"); 

if (logFile == null) 
{ 
	logFile = space.createFile("GroupAndUsers.txt"); 
} 

// return all results, skip 0
var paging = utils.createPaging(-1, 0);

siteGroups = groups.getGroups(null, paging); 

for (var i=0; i<siteGroups.length; i++) 
{ 
	if (siteGroups[i].displayName.indexOf("gl_aa_alfresco_") == -1 && 
		siteGroups[i].displayName.indexOf("gl_center_") == -1 &&
		siteGroups[i].displayName.indexOf("site_") == -1)
	{
		
		logFile.content += siteGroups[i].displayName + "\n"; 
	
		var group = people.getGroup(siteGroups[i].id); 
		var members = people.getMembers(group,false); 
		
		for (var member in members) 
		{ 
			logFile.content += member.properties.userName + "\n";
		}
	}
} 

logFile.save(); 
logFile.content; 1‍2‍3‍4‍5‍6‍7‍8‍9‍10‍11‍12‍13‍14‍15‍16‍17‍18‍19‍20‍21‍22‍23‍24‍25‍26‍27‍28‍29‍30‍31‍32‍33‍34‍
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But line

var members = people.getMembers(group,false);

gives an error. What is wrong?

Using Alfresco 5.0.3.

Thanks,

Patrick

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Accepted answers

jpotts

The error is that the group you are passing is not defined. This is because when you call people.getGroup you are passing in siteGroups[i].id but there is no "id" property of a SiteGroup object.

Instead, try passing in siteGroups[i].fullName, see ScriptGroup object | Alfresco Documentation

All comments

patrickvanhoof

Error message is:

2019-01-28 14:09:18,134 ERROR [org.springframework.extensions.webscripts.AbstractRuntime] [http-apr-8080-exec-45] Exception from executeScript - redirecting to status template error: 002815346 Failed to execute script 'workspace://SpacesStore/7eb39344-f918-40e8-8d96-ddaa60be2b09': Group is a mandatory parameter
org.alfresco.scripts.ScriptException: 002815346 Failed to execute script 'workspace://SpacesStore/7eb39344-f918-40e8-8d96-ddaa60be2b09': Group is a mandatory parameter

jpotts

The error is that the group you are passing is not defined. This is because when you call people.getGroup you are passing in siteGroups[i].id but there is no "id" property of a SiteGroup object.

Instead, try passing in siteGroups[i].fullName, see ScriptGroup object | Alfresco Documentation

patrickvanhoof

Thanks Jeff, that works. But one more question concerning getting the users per group. I have code

		var group = people.getGroup(siteGroups[i].fullName); 
		var members = people.getMembers(group,false); 

		for (var member in members) 
		{ 
			var memberNode = people.getPerson(member.userName); 
			
			if (memberNode != null)
			{ 
			
				logFile.content += " - " + memberNode.properties["lastName"] + ";" + memberNode.properties["firstName"] + ";" + memberNode.properties["email"] + "\n";
			} 
		}
‍‍‍‍‍‍‍‍‍‍‍‍‍

but I do not get any users listed in logFile... so I must do something wrong there too...

Any help much appreciated!

roberto_gamiz

Hello,

With code line "for (var member in members)" what you are really doing is an iteration through indexes of the array members .

So to access each individual member object you need to write members[member] inside the loop.

Your code should be somethig like:

var group = people.getGroup(siteGroups[i].fullName); 
var members = people.getMembers(group,false); 

for (var member in members) 
{ 
     var memberNode = people.getPerson(members[member].properties["userName"]); 
     if (memberNode != null)
     {
          logger.log(" - " + memberNode.properties["lastName"] + ";" + memberNode.properties["firstName"] + ";" + memberNode.properties["email"]);
     } 
}‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Regards

patrickvanhoof

It should just be

for (var j=0; j<members.length; j++) 
{
	logFile.content += " - " + members[j].properties.lastName + ";" + members[j].properties.firstName + ";" + members[j].properties.email + "\n";
}	
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