nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

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Alfresco Content Services

Accepted answers

angelborroy

Hope this helps: https://github.com/keensoft/alfresco-datalist-constraints/blob/master/datalist-model-repo/src/main/java/es/keensoft/alfresco/action/webscript/DataListWebScript.java

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ratik_singhal

Hi,

try either two.. Hope you will be able to retrieve the association.

(1)

List<ChildAssociationRef> nodes = nodeService.getChildAssocs(node);
List<ChildAssociationRef> testAssociate = new List<ChildAssociationRef>();
for (ChildAssociationRef element : nodes) {
if ("testAssociate".equalsIgnoreCase(element.getTypeQName().toString())) {
testAssociate.add(element);
}
}

(2)

nodeService.getChildAssocs(parentNodeRef, ContentModel.ASSOC_CONTAINS, RegexQNamePattern.MATCH_ALL);

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Hope this helps: https://github.com/keensoft/alfresco-datalist-constraints/blob/master/datalist-model-repo/src/main/java/es/keensoft/alfresco/action/webscript/DataListWebScript.java

ratik_singhal

yes

anon26949

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anon26949

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