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Searching for PATH children

marcus

I'm wanting to get all the children of a specific node, which after reading the docs seemed like it should be achievable by doing something like the following

Node node = new Node(someNodeRef);
String query = "PATH:\""+node.getPath()+"/*\"";
[code]

However, for some reason it only seems to work if I replace the full namespace URIs (eg "{http://www.alfresco.org/model/application/1.0}") with the shortened versions ("app:") in the path. 

This is with 1.4p.‍‍‍‍‍‍‍‍

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Comments

andy

Hi

That is correct. It uses the XPATH prefix style.

Node node = new Node(someNodeRef);
String query = "PATH:\""+node.getPath().toPrefixString(resolver)+"/*\"";
‍‍‍‍

Will give the correct path (prefixes and encoding of non allowed characters in PATH/XPATH)

Regards

Andy

marcus

That makes sense, however node.getPath() returns a String value. Am I missing something here?

kevinr

The issue is the Node class you are using (the web-client Node wrapper) returns the String version of the Path. You want the underlying repository Path object. This code should work in the web-client:

NodeService nodeService = Repository.getServiceRegistry(FacesContext.getCurrentInstance()).getNodeService();
Node node = new Node(nodeRef);
String query = "PATH:\"" + nodeService.getPath(nodeRef).toPrefixString(resolver) + "/*\""; 
‍‍‍‍‍

Thanks,

Kevin

marcus

Funny, I stumbled on this just before I got a notify email

. However, I can't figure out what Namespace resolver I should be using; not just for this instance, but in other cases too. Are there rules about what resolver to use where?

kevinr

use the ServiceRegistry to get the NamespaceService as that supports the resolver interface for Alfresco and custom models.

Thanks,

Kevin