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Permission API

spring777

Hi everyone,

Suppose the following code :

<#if user.isAdmin>
<span><a href="${url.context}/proxy/alfresco${version.downloadURL}" class="download">${msg("link.download")}</a></span>
</#if>
‍‍‍‍‍

I am looking for a similar expression that make display the span only if the user role for the current node is different from a role X (added role) which is supposed to be a consumer without the download ability

I tried all combinations of the userhome and permissions objects but I got always something like this :

Exception: freemarker.core.InvalidReferenceException - Expression userhome is undefined on line 45, column 38 in org/alfresco/components/document-details/document-versions.get.html.ftl.
freemarker.core.TemplateObject.assertNonNull(TemplateObject.java:124)
….
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Comments

kriton

I had a similar question. This is how I solved it:

On the controller file for your webscript (should be a file with the same name as the .ftl one but with a .js extension) do the following:

model.permissions = AlfrescoUtil.getSiteMembership(model.site).role ;‍

Then on your ftl file of the webscript you can do this check :

<#if permissions!="SiteConsumer" >
<span><a href="${url.context}/proxy/alfresco${version.downloadURL}" class="download">${msg("link.download")}</a></span>
</#if>‍‍‍

You can replace SiteConsumer with any role you like.

spring777

Hello,

Can you post the content of AlfrescoUtil.getSiteMembership function, it doesnt exist in my Alfresco

Thank you

kriton

Alfresco utils library is located in this fodler: share\WEB-INF\classes\templates\org\alfresco\import\alfrsco-util.js

You should import it in your js controller like this :
<import resource="classpath:/alfresco/templates/org/alfresco/import/alfresco-util.js">

Perhaps thats missing from your code ?

If not, this is the code pasted from that file:

   
   /**
    * Retrieve current user's site membership.
    *
    * @method getSiteMembership
    * @param siteId {string} Site to get details for
    * @return {object} Object literal of the form
    * <pre>
    *    isMember: true|false,
    *    isManager: true|false
    *    role: "SiteManager"|"SiteCollaborator"|"SiteContributor"|"SiteConsumer"
    * </pre>
    */
getSiteMembership: function getSiteMembership(siteId)
   {
      var obj =
      {
         isMember: false,
         isManager: false,
         role: ""
      };

      var json = remote.call("/api/sites/" + encodeURIComponent(siteId) + "/memberships/" + encodeURIComponent(user.name));
      if (json.status == 200)
      {
         response = eval('(' + json + ')');
         if (response)
         {
            obj =
            {
               isMember: true,
               isManager: response.role == "SiteManager",
               role: response.role
            };
         }
      }
      return obj;
   }‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

However this might not help you, as it calls another webscript within alfresco that return a json response about the current user's site membership status. That webscript might be missing on your version as well ? I have no alfresco experience prior to 4.0 so I may be unable to help you there.
You can test if you have that webscript by running http://yourserver/alfresco/service/api/sites/{siteid}/memberships/{username}
You should see a json response on your browser.

spring777

All that is missing in version 3.4, I will install Alfresco 4 and try to copy stuff in 3.4

before that I want just to ensure something, do this function really return the current user's role for the CURRENT NODE ?

kriton

It returns the user's role for the given site.

spring777

Ok thank you so much Kriton

rudyantolin

How about if I try to extend the download link to be watermark-first-then-download link? Are there any possibilities to add extended permission API to my new watermark-first-then-download link?

Best Regards,
Rudyanto