What is the best way to list the content of a folder ?

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sam69

Hello !
First of all, I am a newbie in the Alfresco WebServices, but I have already read the WebService Samples.
I can't really find an example to do this simple task:

I want to get all the items (documents and folder) of a specific folder.
I tried that :

RepositoryServiceSoapBindingStub repositoryService = WebServiceFactory.getRepositoryService();       
    Reference reference = new Reference(new Store(StoreEnum.workspace, "SpacesStore")
        , null, "/app:company_home/*[@cm:name=\"" + Data Dictionary + "\"]");
    Predicate predicate = new Predicate(new Reference[]{reference}, null, null);
    
    Node[] nodes = null;
    try
    {
      nodes = repositoryService.get(predicate);

      for (Node n : nodes) {
        System.out.println(n.toString());
        }
      }
‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

And the result is only :
org.alfresco.webservice.types.Node@8f8b47fd
But there are several elements in the folder Data Dictionary 😞

I suspect my Xpath query…
And I think also that there is a better and faster way to do what I want.

Anyone can help me ?

Thanks in advance !

Regards,
Samuel

andy

Hi

"/app:company_home/*[@cm:name=\"" + Data Dictionary + "\"]"

Should find the data dictionary folder (well all folders called DD)

If you want the top level children
"/app:company_home/*[@cm:name=\"" + Data Dictionary + "\"]/*"

If you want all the children
"/app:company_home/*[@cm:name=\"" + Data Dictionary + "\"]//*"

However these queries are not the most efficient.

I would recommend you find the DD node and then run the query in this context with "./*" or ".//*" to find the children or all descendants respectively.

Regards

Andy