nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

As we transition to the new Hyland Community, some post links may be temporarily disrupted as we finalize redirects. We apologize for the inconvenience and are working to resolve this as quickly as possible. Details.

Server-side javascript : equals() or == ?

dgenard

Hi,

how does the Alfresco javascript engine computes equality ?

In regular javascript, the == operator returns true if 2 string values have the same content.
In Java, we know that the meaning isn't the same. We use equals() method to compare the content of 2 strings.

After some investigations, I did notice that Alfresco javascript engine doesn't follow the javascript meaning of == for node properties.
In example, this might not be true

document.id == doc.id‍

even if document and doc represent the same node.
In this case,

document.id.equals(doc.id)‍

returns true.

I don't know if this is a bug or feature…
This applies to Alfresco 2.1.0E.
What is the valid way to test equality of 2 node properties in Alfresco server-side javascript ?

Denis

Find more posts tagged with

Comments

kevinr

The problem is that some of the strings you have are actually Java java.lang.String objects and some are javascript 'string' objects. If you do this:

var id = new String(document.id);
if (someid == id)
{…}
‍‍‍‍‍

then it should work.

Kevin

louise

Same problem here, but the solution (.toString() isn't helps):

if(String(first_node.nodeRef) === String(second_node.nodeRef)) {
  … same nodeRef
} else {
  … different
}
‍‍‍‍‍‍‍

sbuckle

I take it the two node references you are comparing ARE the same? I can't see anything wrong with the example JavaScript you gave. Based upon your example I came up with a quick test:

// your noderef here
var nodeRef = "workspace://SpacesStore/4658fedc-f431-45fr-b834-c7a7441zs624";

var x = search.findNode(nodeRef);
var y = search.findNode(nodeRef);

if (String(x.nodeRef) === String(y.nodeRef)) {
  logger.log("Equal");
} else {
  logger.log("Not equal");
}
‍‍‍‍‍‍‍‍‍‍‍‍‍

As expected, it prints out "Equal" in the log.